Calculating a Line Integral with Greens Theorem

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gtfitzpatrick
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Homework Statement



Calculate [itex]\oint _c xdy-ydx[/itex] where C is the straight line segment from[itex](x_1 , y_1) to (x_2 , y_2)[/itex]

Homework Equations


The Attempt at a Solution



so from Greens theorem I get [itex]\oint _c xdy-ydx[/itex] = [itex]\int\int \frac{\partial x}{\partial x} + \frac{\partial y}{\partial y} dxdy[/itex]

=2 [itex]\int^{x_2}_{x_1}\int^{y_2}_{y_1} dydx[/itex]
=2[[itex](y_2 - y_1)(x_2 - x_1)[/itex] ]
 
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gtfitzpatrick said:

Homework Statement



Calculate [itex]\oint _c xdy-ydx[/itex] where C is the straight line segment from[itex](x_1 , y_1) to (x_2 , y_2)[/itex]

Homework Equations





The Attempt at a Solution



so from Greens theorem I get [itex]\oint _c xdy-ydx[/itex] = [itex]\int\int \frac{\partial x}{\partial x} + \frac{\partial y}{\partial y} dxdy[/itex]

=2 [itex]\int^{x_2}_{x_1}\int^{y_2}_{y_1} dydx[/itex]
=2[[itex](y_2 - y_1)(x_2 - x_1)[/itex] ]

For Green's theorem you need a line integral along a curve which encloses an area. You don't have that so Green's theorem has nothing to do with this problem. Just work the line integral itself out.
 
Hi LCkutz,
Aghhh so he threw it in as a trick question into the greens theorem section. Sneeky!
Thanks LC