Engineering Calculating AC Current with a 1.5e-6 F Capacitor: 1kHz vs 8kHz Frequencies

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To calculate the amplitude of the alternating current through a 1.5e-6 F capacitor connected to a 30 V AC generator, the formula \(\frac{1}{2 \pi f c}\) is essential for determining capacitive reactance. At frequencies of 1 kHz and 8 kHz, the reactance will differ, affecting the resulting current amplitude. The discussion emphasizes the importance of understanding how frequency impacts capacitive resistance in AC circuits. Participants are encouraged to post homework questions in the designated section for better guidance. The thread highlights the need for clarity in problem-solving and adherence to forum guidelines.
carrollitis
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A 1.5e-6 F capacitor is connected as in fig. 31-10 to an AC generator with Em=30 V. What is the amplitude of the resulting alternating current if the frequency of the emf is (a) 1kHz and (b) 8kHz?

I have no idea where to begin. I don't even know what they are asking for in this problem.
 
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Does \frac{1} {2 \pi f c} help?
 
If you can show me how to do the entire problem that would be great.
 
PF guidelines are that you need to show your attempt at a solution.
Also you should have posted it in the homework section.
 
How do I do that?
 
carrollitis said:
How do I do that?

The homework section is located here:
https://www.physicsforums.com/forumdisplay.php?f=152
Post your homework questions in that section from now. Do not start another thread about this because I've already requested a move.

Tell us about the ac resistance of a capacitor and how frequency effects, if anything at all.
 
carrollitis said:
How do I do that?

NoTime said:
Does \frac{1} {2 \pi f c} help?

Does this post from NoTime mean nothing at all to you?

It's a very big hint...
 

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