Calculating Acceleration and Time for a Freight Train to Reach 83.4 km/hr

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To calculate the time it takes for a freight train to accelerate from rest to 83.4 km/hr, the acceleration must first be determined using F=ma. The train's mass is 1.20E+7 kg, and the locomotive exerts a force of 6.10E+5 N, resulting in an acceleration of approximately 0.050833 m/s². The final velocity of 83.4 km/hr converts to 23.16 m/s. Using the equation v = u + at, the time required to reach this speed is calculated to be about 455.6 seconds. Accurate unit conversion is crucial for obtaining correct results in such calculations.
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hi
could someone please tell me where i am going wrong with this question:
A freight train has a mass of 1.20E+7 kg. If the locomotive can exert a constant pull of 6.10E+5 N, how long does it take to increase the speed of the train from rest to 83.4 km/hr?
i tried to find accelertion by using F=ma, and i keep getting 0.05833...then i put it into the equation v=vo+at, but my answers never turn out right. i think maybe unit conversion is where I'm going wrong...but I'm not sure.
help would be appreciated...
thanks, lilly
 
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Lilly said:
i tried to find accelertion by using F=ma, and i keep getting 0.05833...
Right method. I assume that's a typo, since I get 0.050833 m/s^2.
then i put it into the equation v=vo+at, but my answers never turn out right. i think maybe unit conversion is where I'm going wrong...but I'm not sure.
Sounds good to me. If you aren't sure of your conversion, show how you did it.
 
I think this would help

My Acceleration is 0.0508333
83.4 KM/Hr = 83.4 * 5/18 m/sec = 23.16 m/sec which is the final velocity.
So according to the formula you used, u = uo + at my value for t turns out to be 23.16/0.0508333 = 455.6 seconds.
 
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