Calculating Acceleration of a 2.60 kg Object with Given Tensions and Angle

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To calculate the x-component of acceleration (ax) for a 2.60 kg object with given tensions and an angle, the net force in the x-direction must be determined. The equation F netx = m * a is used, where the net force is calculated by considering the contributions from all relevant tensions, including T1, T3, and T4. The user initially attempted to calculate ax using only T1 and T3, neglecting T4's x-component. Accurate results require including all forces acting in the x-direction. Properly accounting for all tensions will yield the correct acceleration value.
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Homework Statement


The tensions of the ropes acting on a 2.60 kg object are shown. Find the value of ax, the x-component of the acceleration, if T1=1.40 N, T2=2.80 N, T3=3.20 N, T4=4.70 N, and θ=12.0°? Diagram:
http://img19.imageshack.us/img19/3733/knpic0506bnew.png


Homework Equations


F netx = m * a
a = F netx / m


The Attempt at a Solution


Well, I added the two forces in the X direction simply by doing:

T1 * Cos θ - T3 = m*a

a = ( T1*Cos θ - T3 )/ a

However, I keep getting the wrong answer. Can anyone help me out? Thanks
 
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crazy_nuttie said:

The Attempt at a Solution


Well, I added the two forces in the X direction simply by doing:
Looks like three of those forces have x-components. What about T4?
 

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