Calculating Amplifier Power Draw from +9v and -9v Batteries - 8mA Current

AI Thread Summary
To calculate the power drawn from the +9V and -9V batteries by the amplifier, the relevant equation is P = VI, where V is the total voltage difference and I is the current. The amplifier draws 8mA from each battery, resulting in a total current of 8mA for each supply, not canceling out. The total voltage across the batteries is 18V (9V + 9V), leading to a power calculation of P = 18V * 0.008A, which equals 0.144W. Understanding that the currents from both batteries contribute to the amplifier's power draw is crucial for the calculation. The power delivered by the batteries is equivalent to the power consumed by the amplifier.
PhysicsThrow
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Homework Statement


Calculate the power drawn from the batteries by the amplifier. The batteries are +9v and -9v.
The amplifier draws a current of 8mA from each of its power supplies.

Homework Equations


P = VI

The Attempt at a Solution


I'm just a little stumped as to what to do for the current. I know V = 18v but I'm not sure how the 2 currents interact with each other. Do they cancel out? Do they multiply or sum up?
I'm sure I can finish the rest if I understand that.
 
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I take it we are supposed to guess what the circuit that you are talking about looks like
 
cj1Bzpv.png


VCC = 9V
VEE = -9V
VO = 6v rms
VI = 2v rms
RL = 900Ω
Amplifier draws 8mA from each battery.
Input sinusoidal current of 1v rms.

So the terms relevant to the amplifiers power draw are
VCC, VEE and the 8mA current from each battery.

I assume I just calculate using P = VI = (9*2)*I
But I can't work out what I should equal. Is it (8mA*2) or (8mA+-8mA=0)? Or is it just 8mA?
 

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Vcc and Vee are drawn as identical in direction yet you have said one is positive and one is negative. Why is that?
 
PhysicsThrow..

Hint: Forget the amplifier, just look at the batteries. What current is flowing through each battery? If you can't see it, move your symbols for ICC and IEE nearer the batteries on the drawing. How much power are the batteries delivering? That's the same as the amplifier is drawing (with no signal)

Still stuck? Apply KCL to he node between the two batteries. Is there any current flowing in the ground wire?
 
Last edited:
PhysicsThrow said:

Homework Statement


Calculate the power drawn from the batteries by the amplifier. The batteries are +9v and -9v.
The amplifier draws a current of 8mA from each of its power supplies.

Homework Equations


P = VI

The Attempt at a Solution


I'm just a little stumped as to what to do for the current. I know V = 18v but I'm not sure how the 2 currents interact with each other. Do they cancel out? Do they multiply or sum up?
I'm sure I can finish the rest if I understand that.

The batteries are the power supplies I assume.

So the answer is too obvuious to give any hints.
 

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