Calculating Amplitude and Phase for Superimposed Harmonic Oscillators

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To calculate the resultant amplitude and phase of two superimposed harmonic oscillators, start by determining the individual wave equations based on their amplitudes and phase difference. The first oscillator has an amplitude of 5 mm, while the second has an amplitude of 3 mm with a phase shift of 30°. Graphing the two waves can provide a visual understanding of their superposition and resultant amplitude. The mathematical approach involves using trigonometric identities to combine the amplitudes and phases. This method will yield the resultant amplitude and phase relative to the first component.
kidia
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Can anybody give me the hint where to start on this question?

Two simple harmonic oscillators of the same frequency and in the same direction having amplitudes 5 mm and 3 mm, respectively and the phase of the second component relative to the first is 30°, are superimposed. Find the amplitude of the resultant oscillation and its phase relative to the first component.
 
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Whether or not it will suffice as "properly done," try manually graphing these waves on graph paper (two cycles of each wave, max), and adding their amplitudes to find the superimposed amplitude. It will give you insight to what is going on.

If you need to show the math, begin by finding the expression for amplitude for each wave as a funtion of wt.
 
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