I've tried this problem at least 10 times using the equations in my book and I keep getting the same answer. What am I doing wrong? 1. The problem statement, all variables and given/known data A solid steel sphere of density 7.6 g/cm3 and mass 0.2 kg spin on an axis through its center with a period of 1.5 s. Given Vsphere =4/3π^3, what is its angular momentum? Answer in units of kg m2/s 2. Relevant equations Angular momentum=Moment of inertia*angular velocity Moment of inertia for a solid sphere=2/5MR^2 Volume=Mass/Density Vsphere=4/3π^3 Angular velocity=2π/period 3. The attempt at a solution Angular velocity=2π/1.5= 4.18879rad/s Volume of sphere=.2kg/.0076kg/cm^3=26.3158cm^3 Radius of sphere=[26.3158cm^3/(4π/3)]^(1/3)=1.845197cm =0.01845197meters I=(2/5)(.2kg)(0.01845197m)^2=.000027238 kg/m^2 Angular momentum=(.000027238kg/m^2)(4.18879rad/s)=0.000140973359kg/m^2/s I thought my answer was correct but my university's homework page keeps telling me that is it wrong. Anyone know where I am going wrong in this problem?