Calculating angular momentum of a sphere

[BBC of peace]

I've tried this problem at least 10 times using the equations in my book and I keep getting the same answer. What am I doing wrong?

Homework Statement

A solid steel sphere of density 7.6 g/cm3
and
mass 0.2 kg spin on an axis through its center
with a period of 1.5 s.
Given Vsphere =4/3π^3, what is its angular momentum?
Answer in units of kg m2/s

Homework Equations

Angular momentum=Moment of inertia*angular velocity
Moment of inertia for a solid sphere=2/5MR^2
Volume=Mass/Density
Vsphere=4/3π^3
Angular velocity=2π/period

The Attempt at a Solution

Angular velocity=2π/1.5= 4.18879rad/s
Volume of sphere=.2kg/.0076kg/cm^3=26.3158cm^3
Radius of sphere=[26.3158cm^3/(4π/3)]^(1/3)=1.845197cm =0.01845197meters
I=(2/5)(.2kg)(0.01845197m)^2=.000027238 kg/m^2
Angular momentum=(.000027238kg/m^2)(4.18879rad/s)=0.000140973359kg/m^2/s

I thought my answer was correct but my university's homework page keeps telling me that is it wrong. Anyone know where I am going wrong in this problem?

 

[BBC of peace]

Nevermind, I guess I typed in the answer wrong. My solution was correct.

 

[ehild]

The numerical result is correct, but the unit is wrong. The unit of moment of inertia is kgm². And give the result in normal form (scientific notation) with two significant digits.

ehild