courtrigrad
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If y = \frac{x^{3}}{6} + \frac{1}{2x}\ and \frac{1}{2}\leq x\leq 1. Find the arc length.
So \frac{dy}{dx} = \frac{x^{2}}{2} - \frac{1}{2x^{2}}. So I got \frac{1}{2} \int^{1}_{\frac{1}{2}} \sqrt{2+x^{4} + x^{-4}} dx. How would you evaulate this?
Thanks
So \frac{dy}{dx} = \frac{x^{2}}{2} - \frac{1}{2x^{2}}. So I got \frac{1}{2} \int^{1}_{\frac{1}{2}} \sqrt{2+x^{4} + x^{-4}} dx. How would you evaulate this?
Thanks
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