Calculating Arrow Flight Time: Solving for Distance and Angle

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To calculate the time taken for an arrow shot at a 45-degree angle to land 100 meters away, separate equations for vertical and horizontal motion can be utilized. By assuming no air resistance, the equations can be solved simultaneously without needing the initial velocity, which can be represented as "v." This approach simplifies the problem significantly. The realization that the solution is straightforward highlights the importance of breaking down the motion into its components. Understanding these principles can aid in solving similar projectile motion problems effectively.
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If an arrow is shot at an angle 45 to the horizontal, and lands in the ground a distance(same height as it was shot) 100m away, is it possible to work out the time taken? I can't figure it out...I have been messing around with equations, but because we don't have an initial velocity I can't get it.


Any ideas?
 
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Assuming you can ignore the complications of air resistance, you should be able to figure it out. Hint: Write separate equations for vertical and horizontal position as a function of time. Then solve them together, making use of the given information. (You don't need to know the initial velocity--just call it "v".)
 
Cheers for the input:smile:

I don't know how I didn't realize it was that simple!
 
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