Calculating Ascension Rate of a Helium Balloon

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Discussion Overview

The discussion revolves around calculating the accelerating ascension rate of a helium balloon under ideal conditions, excluding factors such as volume change, temperature, and wind. Participants explore the relevant equations and concepts related to buoyancy and forces acting on the balloon.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant seeks to find the accelerating ascension rate using a specific formula: a = g*(rho_f * V - m)/(rho_f*V + m), questioning its correctness and computation.
  • Another participant notes that for a non-accelerating ascent, buoyancy and air friction forces would balance each other.
  • A later reply clarifies the focus on the accelerating rate and suggests using T=ρfVg-mg to find the initial upward force, leading to the initial acceleration calculation ai=T/m.
  • One participant claims to have calculated an acceleration of 13.490311 m/s², repeating the result for confirmation.
  • Another participant inquires about determining the constant non-accelerating ascent due to air friction.
  • A participant comments on the shape of the balloon, suggesting it resembles a teardrop with specific characteristics, indicating a consideration of aerodynamic factors.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the correctness of the initial formula and calculations. There is no consensus on the final answer or the approach to finding the constant ascent due to air friction.

Contextual Notes

Participants do not address potential limitations of the assumptions made in their calculations, such as the effects of changing volume or temperature on the balloon's ascent.

Who May Find This Useful

Individuals interested in buoyancy, fluid dynamics, or those working on practical applications related to balloon ascension may find this discussion relevant.

Imustthink
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How do I find the accelerating ascension rate of my helium balloon?
Ignore factors such as the increase of volume as it ascends, temperature, wind etc.
I just want the basic ascension rate of ideal non changing conditions.

rho_f Outside air density - I think typical air density is this - 1.2 kg/m^3

v Volume - 179.59438 m^3

m Mass - 90.7184 kg

g Earth's gravity - 9.80665 m/s^2

Through some research I have been given this formula but am not sure if its the correct one or how to compute it.

a = g*(rho_f * V - m)/(rho_f*V + m)

And also this link

http://en.wikipedia.org/wiki/Buoyancy#Beyond_Archimedes_Principle
 
Last edited:
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For a non-accelerating ascent, the upward force of buoyancy will be balanced by a downward force due to air friction.
 
(edited) I meant the accelerating rate, sorry
 
OK. Use the T=ρfVg-mg equation from your Wikipedia article to find the initial upward force.

The initial acceleration is then, ai=T/m.
 
So if I did this correctly the answer is: 13.490311 m/s^2 ?
 
Imustthink said:
So if I did this correctly the answer is: 13.490311 m/s^2 ?

That's the answer I get.
 
Giga-thanks!
 
How would I find the constant non accelerating ascent due to air friction? haha
 
Under Mechanical Engineering there's a Aerospace Engineering subfolder. I take it this balloon would take the shape of a teardrop, flattened on the nose, with a lot of wrinkles. I'm not touching that one.
 

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