Calculating Average Age in a Solera Process

shinta
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Hi, I'm trying to figure out the average age in a solera process. The equations are:

An = (2/3)(An-1 + 1) + (1/3)(0)
Bn = (2/3)(Bn-1 + 1) + (1/3)(An-1 + 1)
Cn = (2/3)(Cn-1 + 1) + (1/3)(Bn-1 + 1)

With initial state:

A0 = 0
B0 = 0
C0 = 0

The question is, what is C as n goes to infinity?
 
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Find the limiting value of An as n -> infinity.
Substitute this value into the difference eqn for Bn.

Find the limiting value of Bn as n -> infinity.
Substitute this value into the difference eqn for Cn.

And finally, find the limiting value of Cn as n -> infinity.

I also wrote a small program to work out the values of the series, and got the limiting value for Cn as Cn = 8.00000...
 
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If you assume that they all converge to a, b and c respectively then they satisfy

a=(2/3)(a+1) + 1/3

b=(2/3)(b+1) +(1/3)(a+1)

c = (2/3)(c + 1) + (1/3)(b + 1)

which you can solve.

So, if there is a solution, that is what it is. You might need to prove that a limit exists, though.
 
Hey, thanks for the help guys.

Ya, I figured out later to just substitute a_n = a_n+1 and solve. I suppose I should prove that the series converges, but this is good enough for now.

Thanks!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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