Calculating Average Power for Acceleration: 630 kg Car, 0-65 mi/h in 6.0 sec

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To calculate the average power needed to accelerate a 630 kg car from 0 to 65 mph in 6.0 seconds, the change in kinetic energy must be correctly calculated using the formula (1/2)mv². The initial calculation of 20475 J is incorrect due to unit inconsistency and misapplication of the kinetic energy formula. It's crucial to convert 65 mph to meters per second before performing any calculations. The average power can then be determined using the formula P = W/t, where W is the work done, expressed in Joules. Proper unit conversion and formula application are essential for accurate results.
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What is the average power needed to accelerate a 630 kg car from 0 to 65 mi/h in 6.0 seconds? Assume that all forms of frictional losses can be ignored.

i've calculated change in kinetic energy to be 20475 J using: 1/2mv(final) - 1/2mv(initial). Since, change in kinetic energy is equal to work, i applied it to P = W/t. The answer I am getting is wrong and I've also tried converting mi/h to m/s and the answer is still not right, what am i doing wrong??
 
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it looks like you used 65 mph in your calculation!

You should try to be consistent with your units.
If you're going to have the work done expressed in Joules, then use SI units all the way. Convert the speed to metric first of all.

Oh yes, the formula you used is incorrect, I'm afraid.
The KE is given by (1/2)mv² - not (1/2)mv.
 
To get joules, you're going to have to convert miles/hour to m/s. It's best to do this before you try and calculate Work. What's the final speed of the car in m/s?
 
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