Calculating Averages in a Unidimensional Quantum System

dirac68
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Homework Statement



Hi, i would to resolve this problem of quantum mechanics.

I have hamiltonian operator of a unidimensional system:

\hat{H}={\hat{p}^2 \over 2 m}-F\hat{x}

where m and F are costant; the state is described by the function wave at t=0

\psi (x, t=0)=A e ^{-x^2-x}

where A is a costant.

How can I calculate the the avarage of x and p at time t after t=0 ( so <x>_t and <p>_t )?

what is the fast procedure to solve it?

Homework Equations


\hat{H}={\hat{p}\over 2 m}-F\hat{x}

\psi (x, t=0)=A e ^{-x^2-x}

The Attempt at a Solution



I found a solution but it seems very long and boring...
 
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\psi(x,t)=\psi(x,0)e^{-iEt/\hbar}... where E is given by: \hat{H}\psi=E\psi

note: shouldn't the momentum operator appear squared in that hamiltonian?
 
Simon Bridge said:
\psi(x,t)=\psi(x,0)e^{-iEt/\hbar}... where E is given by: \hat{H}\psi=E\psi

note: shouldn't the momentum operator appear squared in that hamiltonian?

oh yes it's p2/2m... but find eigenvalue E is too hard!
 
Use the Ehrenfest theorem.
 
avarage of x and p
Ahhh yes - that's easier.

You don't have discrete E eigenvalues because you don't have a lower bound - but you don't need them. Sorry, my bad.
 
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The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
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