Calculating Binding Energy for Hydrogen Positron Emission

AI Thread Summary
The discussion focuses on calculating the binding energy for hydrogen through positron emission, specifically the reaction 4(11H) → 42He + 2(0+1ß). The initial calculation for binding energy (Eb) was performed using the mass of hydrogen and helium, yielding a result of 2.61 x 10^9 kJ/mol. A critical point raised is the neglect of the mass of the two positrons in the calculation, which could affect the accuracy of the binding energy. The importance of including all products' masses, including positrons, in the mass difference (Δm) is emphasized. Accurate calculations must consider all contributing masses to ensure correct binding energy results.
burg25
Messages
12
Reaction score
0

Homework Statement


Find the binding energy for hydrogen in kJ/mol through positron emission.

4(11H) → 42He + 2(0+1ß)


Homework Equations


E=Δmc2
Mass of Hydrogen: 1.0079 amu
Mass of Helium: 4.0026 amu
1 amu = 1.6605 x 10-27kg


The Attempt at a Solution


Here is what I did:

Eb= ((number of protons)xmass hydrogen)-mass of helium)*1.6605x10-27kg/amu)*c^2
Eb = ((4*1.0079 - 4.0026) * 1.6605*10-27)*(2.998x108)2
Eb= 4.33x10-12 kg m2/s2 = 4.33x10-12 J
Eb = 4.33 x 10-15 kJ
Eb = 4.33 x 10-15 * 6.022 x1023
Eb = 2.61 x 109 kJ/mol
 
Physics news on Phys.org
Haven't you neglected the mass of the 2 positrons?

In the equation, E=Δmc2, the Δm = mass of reactants - mass of all products (including positrons)
 
Isn't a positron basically massless considering it would just have the mass of an electron or will it make a big difference?
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
View full post »

Thread 'Prove that evolution is constant (Provide at least two arguments to support your position)'

I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
View full post »

Similar threads

Finding binding energy from equilibrium bond length
Replies
1
Views
4K
Finding binding energy and converting into MeV
Replies
5
Views
3K
The ionization energy of atomic hydrogen?
Replies
1
Views
20K
What is the binding energy of H-1?
Replies
9
Views
2K
Electron and Proton Binding energy
Replies
1
Views
2K
Gravitational potential energy, orbital speed, binding energy.
Replies
3
Views
3K
What is the Ionisation Energy of Hydrogen in KJ mol-1?
Replies
8
Views
4K
Calculating Energy from Nuclear Reactions
Replies
4
Views
2K
Mass Defect of Hydrogen-2 Electron Binding Energy
Replies
1
Views
6K
AP Chem; Calculating energy released
Replies
1
Views
20K

Hot Threads

Recent Insights

Back
Top