Calculating Binding Energy of Neutron in 14N

AI Thread Summary
The discussion focuses on calculating the binding energy of a neutron in the nitrogen-14 isotope (14N). The mass of nitrogen is given as 14.007 amu, while the calculated mass based on protons, neutrons, and electrons totals 14.115 amu. The difference in mass (delta m) is found to be 0.10839 amu, leading to a calculated binding energy of 1.0096e2 MeV for the entire nucleus. However, the individual binding energy per neutron was incorrectly calculated as 7.21 MeV. A suggestion was made to ensure proper unit conversion when applying the equation E=mc^2 for accuracy.
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Homework Statement



Calculate the binding energy of a neutron in 14N

Homework Equations



E=mc^2

delta m * 1u + E

The Attempt at a Solution



The mass of Nitrogen (from periodic table): 14.007amu

Calculated mass of N:
7 protons (7 * 1.007277amu) + 7 neutrons (7* 1.008665amu) + 7 electrons (7*0.0005486)
=14.115amu

delta m=0.10839 amu

delta m * 1u= 1.0096e2 MeV

After I got the total binding energy I divided by 14 to get the binding energy of one neutron which was 7.21 MeV which was incorrect.
 
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When you had \Delta m =0.10839 amu

did you eventually multiply by 1amu to convert to kg and then multiply by c2?
 
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