Calculating Body Projection: Time, Height & Range

[ProPM]

A body is projected from ground level with a speed of 24 m/s at an angle of 30 degrees above the horizontal. Neglect air resistance and take gravity to be 10 m/s. Calculate:

a) The time taken to reach its highest point
b) The greatest height reached
c) The horizontal range of the body

a) v = u + at
0 = 12 + (-10 x t)
10t = 12
t = 1.2 seconds

b) s = ut + 1/2at^2
s = (12 x 1.2) + (1/2 x -10 x 1.2^2)
s = 7.2 m

c) s = Vertical Velocity (cos 30 x 24) x t

t = 2.4

s = 49.9 m

I tried them, but I am not sure if I made any mistakes.

Can anyone help me?

Thanks!

 

[Delphi51]

Those answers are all correct (assuming g = -10).