Calculating Bullet Speed in Inclined Slide | Mass, Height & Friction Considered

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The discussion focuses on calculating the speed of a bullet before it embeds into a block of wood on an inclined plane. The bullet has a mass of 0.0260 kg, and the block has a mass of 1.30 kg, with the system rising to a height of 1.20 m after the collision. Participants emphasize using conservation of momentum for the collision and conservation of energy for the subsequent motion. One user initially misapplies energy conservation during the impact but later corrects their approach. The correct method involves calculating the velocity of the block and bullet after the collision using energy conservation principles.
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A bullet of mass m= 0.0260 kg is fired along an incline and imbeds itself quickly into a block of wood of mass M= 1.30 kg. The block and bullet then slide up the incline, assumed frictionless, and rise a height H= 1.20 m before stopping. Calculate the speed of the bullet just before it hits the wood. Note. The block is kept from sliding down the incline initially by as small peg (not shown).
I know that I need to use conservation of momentum, but I'm not sure how I would do that since I don't know the final velocity. I don't even know how to find it since I don't know the angle of the incline of the length of the incline.
Any advice?
Thanks
 
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What is the velocity required for the block (with the embedded bullet) to reach a height of 1,20 m?
 
Start by thinking about conservation of energy.
What kind of eqn(s) are/is involved in doing that ?
 
Ok for conservation of energy
I used (1/2)mv_initial^2=Mgh
(1/2)(.0260)v^2= (.0260+1.30)(9.8)(1.20)
Solving for v gave me 34.6 m/s.
Am I doing that right?
 
No, you are not. You cannot assume energy conservation during impact (unless it is stated that the collision is elastic, which is not the case in this problem).

After impact, however, energy is conserved.
 
I figured out what I was doing wrong. Thank you.
 
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