Calculating C for a Freely Falling Satellite

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SUMMARY

The discussion focuses on calculating the constant C for a freely falling satellite using the formula T = C(R^3/GM)^0.5, where G is the gravitational constant and M is the mass of the Earth. The participants clarify that T represents the time taken for the satellite to reach Earth from a distance R, which is significantly larger than Earth's radius. The conclusion drawn is that C equals π/2^(1.5), derived from the equations of motion for the satellite under gravitational influence.

PREREQUISITES
  • Understanding of gravitational forces and the gravitational constant (G).
  • Familiarity with the equations of motion in classical mechanics.
  • Knowledge of the relationship between mass, distance, and acceleration (GM/r^2 = a).
  • Basic grasp of mathematical constants, particularly π.
NEXT STEPS
  • Explore the derivation of gravitational equations in classical mechanics.
  • Study the concept of free fall and its implications in orbital mechanics.
  • Learn about the significance of the gravitational constant (G) in astrophysics.
  • Investigate the mathematical properties of π and its applications in physics.
USEFUL FOR

Students studying physics, particularly those focusing on classical mechanics and gravitational theory, as well as educators seeking to explain the dynamics of freely falling objects in a gravitational field.

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Homework Statement



A satellite falls freely towards the Earth starting from rest at distance R, much larger than the Earth's radius.Treating the Earth as a point mass M then
T=C(R^3/GM)^0.5
where G is gravitational constant
By using equation of motion of the satellite, show that C=pi/2^(1.5)

Homework Equations



use GM/r^2=a


The Attempt at a Solution


I m not sure how the satellite falls ...why is pi in the constant C??
 
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What's T supposed to be?
 
ideasrule said:
What's T supposed to be?

Sorry..T is the time taken by the satellite to reach the Earth
 

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