ideasrule said:What's T supposed to be?
The acceleration of a freely falling satellite can be calculated using the formula a = GM/r^2, where G is the gravitational constant, M is the mass of the planet, and r is the distance between the satellite and the center of the planet.
The velocity of a freely falling satellite can be calculated using the formula v = √(GM/r), where G is the gravitational constant, M is the mass of the planet, and r is the distance between the satellite and the center of the planet.
The time taken for a freely falling satellite to reach the surface of a planet can be calculated using the formula t = √(2h/g), where h is the height of the satellite above the surface and g is the acceleration due to gravity on the planet.
Yes, the acceleration of a freely falling satellite is directly proportional to its mass. This means that a higher mass satellite will experience a greater acceleration due to gravity compared to a lower mass satellite.
The orbital period of a freely falling satellite can be calculated using the formula T = 2π√(r^3/GM), where r is the distance between the satellite and the center of the planet and M is the mass of the planet.