Calculating Capacitance in Closed Loop Circuits

AI Thread Summary
The discussion focuses on calculating capacitance in closed loop circuits, specifically addressing a homework problem. The initial attempt incorrectly used the total voltage of the circuit instead of the voltage across the specific capacitor, C3. The correct approach involves applying voltage divider equations to find the appropriate voltage for C3. The capacitance is calculated by taking the difference in charge between points b and a and dividing it by the voltage across C3. Understanding the distinction between total circuit voltage and the voltage across individual capacitors is crucial for accurate calculations.
Jrlinton
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Homework Statement


upload_2017-2-23_13-10-42.png


Homework Equations


C=Δq/V

The Attempt at a Solution


So part a:
The capacitance of 3 should be the difference in charge of b and a divided by the voltage of the circuit?
C3=(14μC-6μC)/12V
=6.67*10-7 F
This was wrong...
 
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Jrlinton said:
The capacitance of 3 should be the difference in charge of b and a divided by the voltage of the circuit?
No. You need to divide it by the voltage across C3, which is not same as total voltage in the circuit. Use voltage divider equations for capacitive circuits.
 

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