Calculating Capacitance to Limit Voltage in Solenoid

AI Thread Summary
To prevent the voltage generated by the collapsing magnetic field of a solenoid from exceeding 300V when the current is turned off, the minimum capacitance required must be calculated. The solenoid has a self-inductance of 2H and carries a steady current of 1A. The discussion revolves around whether the capacitor is in series or parallel with the solenoid, with a consensus leaning towards parallel configuration. Key equations involve the energy stored in both the inductor and capacitor, which are essential for determining the required capacitance. Understanding the energy dynamics during the oscillation cycle is crucial for solving the problem effectively.
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Homework Statement



A solenoid with self-inductance L=2H and carrying a steady current of 1 A has the current source suddenly turned off. What is the minimum capacitance that should be connected across the terminals of the solenoid in order to prevent the potential difference generated by collapse of the mag field from rising above 300V.

Homework Equations



1/sqrt(LC) = resonance frequency

LD^2 + I/C = 0


The Attempt at a Solution



Are the capacitor and solenoid in series or parallel and I'm not sure exactly where to start.

Sorry that I don't have any work to show.
 
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Connected across the terminals implies that they are in parallel. However, if the solenoid and capacitor are the only remaining components, then one might argue either way:smile:.

You might consider the energy stored in the magnetic field of the solenoid, and what would happen if it were to all be dumped onto the capacitor during the first cycle of oscillation.
 
i guess they're are parallel, but I'm not sure how to find the energy stored? Don't i need the time derivative of current?
 
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