Calculating Centripetal Force for Particle in Circular Motion

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To determine the value of charge Q that allows a moving particle to execute circular motion, the centripetal force must equal the electrostatic force acting on the particle. The formula for the electrostatic force is F = k(qQ/r^2), where k is Coulomb's constant, q is the charge of the moving particle, and r is the distance from the charge Q to the particle. The required centripetal force can be calculated using F = mv²/r, where m is the mass of the particle and v is its velocity. By equating the two forces and solving for Q, the necessary charge for circular motion can be found. Understanding the relationships between mass, velocity, and acceleration is crucial for applying Newton's second law in this context.
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A particle of charge Q is fixed at the origin of an xy coordinate system. At t = 0 a particle (m = 0.694 g, q = 5.04 µC is located on the x-axis at x = 20.2 cm, moving with a speed of 34.0 m/s in the positive y direction. For what value of Q (in μC) will the moving particle execute circular motion? (Neglect the gravitational force on the particle.)

I tried plugging everything in, I just can't seem to figure out where to put the mass or velocity, if at all needed.

does F=k(.00504C)(Q)/(.202^2) ?

I really need somewhere to start
 
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What must the acceleration be, if it's to execute circular motion? Apply Newton's 2nd law.

Note that µC means micro C = 10-6 C.
 
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