Calculating Charge Entering an Element: Q=6.667 C

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The discussion revolves around calculating the charge entering an element with a given current function. The current is constant at 2 A for 0<t<1 seconds and varies as 2t^2 A for t>1 seconds. The participant initially struggled with using the integral method but later realized the correct approach. They calculated the charge for the first interval as 2 C and integrated for the second interval, ultimately confirming the total charge as 6.667 C. The participant expressed gratitude for the clarification that helped them arrive at the solution independently.
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Homework Statement



The current flowing through an element is i = 2 A for 0<t<1 and i = 2t^2 A for t>1
Calculate the charge entering the element from t=0s to t=2s.
Answer: 6.667 C.


Homework Equations


I used Q=t1∫t2 i dt



The Attempt at a Solution


I tried to solve using integral method. but how to proceed here as for 0<t<1 i is constant and i am stuck. Are there any other methods.
 
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I think this is a very basic problem but still I cannot do it because i am a newbie and may be to need work harder. Sorry for consuming your time.
 


If the current is constant over a given time interval, how much charge is accumulated? Remember, 1 ampere = 1 coulomb / second.

Why did you chose the integral method to solve this problem if you cannot integrate a constant function?
 


SteamKing said:
If the current is constant over a given time interval, how much charge is accumulated? Remember, 1 ampere = 1 coulomb / second.

Why did you chose the integral method to solve this problem if you cannot integrate a constant function?
Thank you for pointing out. I made this post in hurry without thinking. And now i got the answer myself.

for 0s to 1s i = 2A so q = 2C

for 1s to 2 s i calculated by integrating i wrt dt between 1s to 2s

and added two values and the answer is correct.
 
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