Calculating Charge & Radius of a Van der Graaff Generator Dome

AI Thread Summary
To determine the charge and radius of a Van der Graaff generator dome with a maximum potential of 600 kV and an electric field of 3.0 MV/m, the relevant equations are E = kq/r^2 and V = kq/r. By substituting the known values into these equations, one can solve for the radius (r) and charge (q). The electric field equation provides a relationship between charge and radius, while the voltage equation connects them through the potential. Solving these equations simultaneously yields the required charge and radius of the dome.
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1. A spherical dome of a Van der Graaff genenerator can be raised to a maximum electrical
potential of 600 kV; then additional charge leaks off in sparks as the electric field reaches 3.0
MV/m. Determine the charge and radius of the dome.



2. Homework Equations [E=kq/r^2 and V=kq/r]



3. I don't know how to relate the given Voltage and the given E field to find charge and radius
 
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You'll use the equations you quoted, for the values given in the problem statement.

I.e.,

3.0 MV/m = kq/r^2
600 kV = kq/r

Work with those to get r and q.
 
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