Calculating Coherence Time: Understanding the Relationship Between g(t) and t_c

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The discussion centers on the coherence time, t_c, and its calculation using the function g(t) = e^{- |t| / t_c}. The user attempts to verify the equation t_c = ∫ |g(t)|^2 dt but encounters issues with the integral's value when evaluated from negative to positive infinity. They mistakenly calculate the integral without properly squaring the function, leading to confusion about the results. Clarification is provided that the correct approach involves recognizing that |g(t)|^2 requires multiplying g(t) by its complex conjugate. The user is encouraged to re-evaluate their integral with this correction in mind.
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Homework Statement



I have the complex term g(t) = e^{\frac{-|t|}{t_c}} which is the degree of the coherence.


Homework Equations



Now I want to verify that:

t_c = \int_{-\infty}^\infty \! |g(t)|^2 \, dt


The Attempt at a Solution



\int_{-\infty}^\infty \! |g(t)|^2 \, dt = \int_{-\infty}^\infty \! |e^{\frac{-|t|}{t_c}}|^2 \, dt = \int_{-\infty}^\infty \! e^{\frac{-|t|}{t_c}} e^{\frac{|t|}{t_c}} \, dt = \int_{-\infty}^\infty \! 1 \, dt

2 Problems now.

First: The integral doesn't have a value if I integrate from - infinity to infinity.
Second: The value of the indefinite integral is t. Not t_c.

What am I missing here?
 
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You didn't multiply ##e^{-\frac{|t|}{t_c}}## by itself. Instead, the second multiplier misses the negative sign. Check your work carefully and try again evaluating the integral.
 
Huh? I'm really missing something here.

|z|^2 = z z^*

So if in my case z = e^{\frac{-|t|}{t_c}} then

z^* = e^{\frac{|t|}{t_c}}

Or not?
 
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