Calculating Collision Frequency of Electrons in Copper Cube

AI Thread Summary
The discussion focuses on verifying the collision frequency of conduction electrons in a copper cube, aiming to confirm the claim of approximately 10^30 collisions per second per square centimeter. The user calculated the number of conduction electrons in copper, arriving at about 8.48 x 10^23 electrons/cm^3 based on copper's density. They also determined the speed of the electrons to be 1.57 x 10^6 m/s using kinetic energy. Suggestions were made to further analyze the time it takes for an electron to travel within the cube and to consider a round trip for more accurate collision frequency calculations. The conversation emphasizes the need for refining the approach to arrive at the correct collision rate.
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Homework Statement
Verify the claim of Section 7.2 that the electrons of a metal collide with the surface at a rate of about 10^30 per second per square centimeter. Do this by estimating the collision frequency of electrons in a 1.00-cm cube of copper metal with one face of the cube surface. Assume that each copper atom contributes one conduction electron to the metal (the chemical valence of copper is 􏰄1) and that these conduction electrons move freely with kinetic energy equal to 7.00 eV.
Relevant Equations
I don't know which equations are relevant for this question.
Homework Statement: Verify the claim of Section 7.2 that the electrons of a metal collide with the surface at a rate of about 10^30 per second per square centimeter. Do this by estimating the collision frequency of electrons in a 1.00-cm cube of copper metal with one face of the cube surface. Assume that each copper atom contributes one conduction electron to the metal (the chemical valence of copper is 􏰄1) and that these conduction electrons move freely with kinetic energy equal to 7.00 eV.
Homework Equations: I don't know which equations are relevant for this question.

First, I just determined the number of electrons per cm^3 knowing the density of copper is 8.95 g.cm^3.
n = 6.02 * 10^23 atoms/mol * 8.95 g/cm^3 * 1 mol/63.5 g = 8.48 * 10^23 electrons/cm^3
I also determined the speed of each electron.
v = sqrt(2E/M) = 1.57 * 10^6 m/s
I just don't know how to proceed from here. Any help would be appreciated!
 
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hnnhcmmngs said:
Homework Statement: Verify the claim of Section 7.2 that the electrons of a metal collide with the surface at a rate of about 10^30 per second per square centimeter. Do this by estimating the collision frequency of electrons in a 1.00-cm cube of copper metal with one face of the cube surface. Assume that each copper atom contributes one conduction electron to the metal (the chemical valence of copper is 􏰄1) and that these conduction electrons move freely with kinetic energy equal to 7.00 eV.
Homework Equations: I don't know which equations are relevant for this question.

Homework Statement: Verify the claim of Section 7.2 that the electrons of a metal collide with the surface at a rate of about 10^30 per second per square centimeter. Do this by estimating the collision frequency of electrons in a 1.00-cm cube of copper metal with one face of the cube surface. Assume that each copper atom contributes one conduction electron to the metal (the chemical valence of copper is 􏰄1) and that these conduction electrons move freely with kinetic energy equal to 7.00 eV.
Homework Equations: I don't know which equations are relevant for this question.

First, I just determined the number of electrons per cm^3 knowing the density of copper is 8.95 g.cm^3.
n = 6.02 * 10^23 atoms/mol * 8.95 g/cm^3 * 1 mol/63.5 g = 8.48 * 10^23 electrons/cm^3
I think you might be off by 1 order of magnitude there. You might want to double check your exponents.
I also determined the speed of each electron.
v = sqrt(2E/M) = 1.57 * 10^6 m/s
I just don't know how to proceed from here. Any help would be appreciated!

Given your velocity calculation, how long would it take for a single electron to travel in a cube of 1 cm length, from one side to the other, if it just moves freely?

Or better yet, since you're only supposed to consider a single side, how long would it take for the round trip: where it starts at one side, bounces off the opposite side, and then returns to the original side?
 
Well the answer varies as it depends on what "level" you have reached. A crude treatment gives answer as $1/6×n×v$ which on refining gives $1/4×n×v$. If you treat electron as Fermi Dirac gas,then the answer is to evaluate partition function and use partition function(See Reif, Fundamentals of Statistical And Thermal Physics)
 
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