Calculating Concrete Materials for 1.68m³ Base

AI Thread Summary
To calculate the materials needed for a concrete base of 1.68 m³ with a ratio of 1 part cement, 2 parts sand, and 3 parts gravel, one must first determine the densities of each material. The total parts of the mix add up to 6, meaning the volume of each component can be calculated based on this ratio. It is essential to convert these volumes into kilograms using the specific densities of cement, sand, and gravel. The discussion highlights the importance of understanding the molecular weights and densities for accurate calculations. Proper calculations will ensure the correct proportions of cement, sand, and gravel are used for the concrete mix.
matfive
Messages
2
Reaction score
0

Homework Statement


hello I have to make a concrete base in metres cubed total 1.68 metres cubed.
The ratio to concrete is 1 part cement to 2 parts sand and 3 parts gravel.
how much cement,gravel, and sand in kilograms?


Homework Equations



?

The Attempt at a Solution


?
 
Physics news on Phys.org
You need to find rough numbers for the density of sand, cement and gravel to do this problem.
 
is it 1/6 times 1.68 metres for cement and how to convert it to kilograms.
 
is it 1/6 times 1.68 metres for cement and how to convert it to kilograms.

Not necessarily. One part (molecule) of cement could take up twice the volume as 1 part (molecule) of sand. You need to know the molecular weight (kg / mol) by knowing the chemical composition as well as the density (in kg/m^3).
 
Last edited:

Thread 'Finding the number of ways to arrange identical balls in a circle (3 different colors)'

I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
View full post »

Thread 'Making the denominator of a certain fraction real'

Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...
View full post »

Similar threads

Materials engineering Concrete
Replies
5
Views
1K
Predicting the Density of Concrete
Replies
3
Views
2K
Residential concrete densifier and sealer?
Replies
8
Views
2K
Hydrostatic Pressure: Resultant Thrust & Overturning Moment
Replies
6
Views
2K
What is the Correct Calculation for Stress in Steel and Concrete?
Replies
11
Views
2K
How to simplify cube root expression
Replies
5
Views
2K
How to Calculate the Edge Length of a Cube Given Its Volume and Surface Area?
Replies
10
Views
2K
Max Drum Rotate Speed of a Concrete Mixer Drum
Replies
9
Views
6K
Engineering Stiffness of a Concrete Core in a Multi-Storey Building
Replies
2
Views
2K
Multiplying different bases with different exponents
Replies
4
Views
1K

Hot Threads

Recent Insights

Back
Top