Calculating Cosine Sum: Solving Complex Equations for Even Roots

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The discussion focuses on calculating the sum of cosines for specific angles related to the equation z^(2n+1) = 1. The sum is interpreted as the sum of the real even roots of this equation. Participants suggest using the relationship between cosine and exponential functions to approach the problem. There is a call for more detailed attempts at solutions to clarify missing steps in the calculations. The conversation highlights the importance of visualizing the angles on the unit circle for solving the equation effectively.
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Homework Statement


Calculate
cos\frac{2\pi}{2n+1} + cos\frac{4\pi}{2n+1} + cos\frac{6\pi}{2n+1} + ... + cos\frac{2n\pi}{2n+1}


Homework Equations


Complex equations, maybe :p

The Attempt at a Solution


Let's say
z^{2n+1} = 1
The sum is equivalent to the sum of the real even roots of the equation above. That's it. Ideas?
 
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Dinheiro said:

Homework Statement


Calculate
cos\frac{2\pi}{2n+1} + cos\frac{4\pi}{2n+1} + cos\frac{6\pi}{2n+1} + ... + cos\frac{2n\pi}{2n+1}


Homework Equations


Complex equations, maybe :p

The Attempt at a Solution


Let's say
z^{2n+1} = 1
The sum is equivalent to the sum of the real even roots of the equation above. That's it. Ideas?

What are YOUR ideas?
 
Those were basically my ideas, I just didn't write down my complete attempt at the solution, sorry. But I could find out what was missing in my resolution xD Thanks, Ray
 
How are we supposed to see what's missing if you don't show us what you did?
 
You mention that, in the complex plane, the given arguments lie equally spaced about the unit circle so did you consider using cos(z)=(e^{iz}+ e^{-iz})/2?
 
Actually, I didn't solve it this way, but nice one though! Thanks, hallsoflvy
 
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