Calculating Current Through Compensation Winding in Cascade Voltage Transformer

AI Thread Summary
The discussion revolves around calculating the current through the compensation winding (Ic) in a cascade voltage transformer setup with two identical units. The user initially calculates Ic as 0.5 A based on their equations, but receives feedback indicating their solution is incorrect without further explanation. They seek clarification on their approach and offer to provide a diagram for better understanding. Another participant confirms the user's calculations are correct and clarifies that "theta" refers to electrical flow. The conversation highlights the need for clear communication and verification in technical discussions.
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Got cascade voltage transformer made from two completely identical units.
On secondary winding, load takes I2=1A
Number of compensation and secondary windings is equal.
I need to find current trough compensation winding Ic
.
θ1 = θ2
--> θ1 = I1N1 + IcNc - I2N2

--> θ2 = I1N1 - IcNc

--> I2N2 = 2IcNc

--> Nc = N2

--> Ic = I2 /2

--> Ic = 0.5 AI did it like this and get feedback that this is wrong without explanation. So, I would be grateful if someone can explain me what is wrong here. I can post scheme if needed.
Thanks in advance.
 
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track said:
Got cascade voltage transformer made from two completely identical units.
On secondary winding, load takes I2=1A
Number of compensation and secondary windings is equal.
I need to find current trough compensation winding Ic
.



θ1 = θ2
--> θ1 = I1N1 + IcNc - I2N2

--> θ2 = I1N1 - IcNc

--> I2N2 = 2IcNc

--> Nc = N2

--> Ic = I2 /2

--> Ic = 0.5 A


I did it like this and get feedback that this is wrong without explanation. So, I would be grateful if someone can explain me what is wrong here. I can post scheme if needed.
Thanks in advance.


Can you post a diagram labelling things? And what is theta?
 
I found this is correct solution, so no need to torture you any moore.

*Theta is electrical flow. If you are interested, I'll sent you sheme.

Regards
 
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