Calculating Current Through JFET Transistor System

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SUMMARY

The discussion centers on calculating the current through a JFET transistor system, specifically an n-type silicon transistor with a grounded source and a reverse-biased gate at 3V. The drain circuit includes a 2000 ohm resistor in series with a 20V supply. The calculated current through the load resistor is 2mA, resulting in an effective resistance of 10000 ohms when considering the series resistor. The calculation relies on understanding the relationship between gate voltage and channel resistance, emphasizing the importance of the transistor's characteristics for accurate current determination.

PREREQUISITES
  • Understanding of JFET transistor operation
  • Knowledge of Ohm's Law
  • Familiarity with circuit analysis techniques
  • Basic concepts of semiconductor physics
NEXT STEPS
  • Study JFET characteristics and transfer curves
  • Learn about load line analysis in transistor circuits
  • Explore the impact of gate voltage on channel resistance
  • Investigate the use of SPICE simulation for JFET circuits
USEFUL FOR

Electrical engineers, electronics students, and hobbyists interested in transistor circuit design and analysis, particularly those working with JFETs.

Hybird
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I have a problem of calculating the current through a system. It is a simple JFET transistor with the source grounded. The gate is reverse biased with a 3v potential, and the drain has a 2000 ohm resistor in series then a positive 20v potential in series which is of course grounded. How would I go about finding the current through the load resistor?
 
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...Assuming an n-type Si transistor

Also I don't have any other information.. I know that the more and more you apply a negative voltage on the gate, the smaller the channel gets which leads to more resistance across the source-drain channel. The answer I am lookin for is 2mA.. that would lead to a resistance of 8000 ohms, cause we still have a 2000 ohm resistor in series therefore 10000 ohm and with a voltage across the source-drain channel of 20 volts.. you get your 2mA answer, I don't see how you can get this bridge voltage without knowing something about a family of curves or the like?
 
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