Calculating current through solenoid?

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Discussion Overview

The discussion revolves around calculating the current in a solenoid using a bar magnet, specifically exploring the application of Faraday's law of electromagnetic induction. Participants are curious about the relationship between the movement of the bar magnet and the induced current in the solenoid.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant suggests using Faraday's law, specifically the equation E=N(dphi/dt), to calculate the current in the solenoid when a bar magnet is moved towards it.
  • Another participant proposes connecting a voltmeter or multimeter across the solenoid to measure the induced voltage as the bar magnet is moved, indicating a change in magnetic flux.
  • A participant clarifies the terms used in the magnetic field equation for a bar magnet, asking if 'M' represents the magnetic strength of each pole and 'r' the distance.
  • Another participant responds by defining 'M' as the magnetic dipole moment and provides a formula for it, including parameters such as the length and radius of the solenoid.

Areas of Agreement / Disagreement

Participants generally agree on the application of Faraday's law and the use of a voltmeter to measure induced voltage, but there are clarifications and definitions that remain open to interpretation.

Contextual Notes

There are unresolved aspects regarding the precise definitions of terms like magnetic dipole moment and the specific parameters involved in the calculations, which may depend on the context of the solenoid and bar magnet setup.

Who May Find This Useful

This discussion may be useful for individuals interested in electromagnetic induction, solenoid behavior, and the practical application of Faraday's law in experimental setups.

scoopaloop
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Not for a class or anything, just out of curiosity, how would you calculate the current in a solenoid, not given a magnetic field, but just using a bar magnet? I know it will just be some form of Faraday's law. E=N(dphi/dt). Maybe not. I'm imagining all I'm really missing is how to calculate the magnetic field of the magnet. Thanks.
 
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Take the solenoid and connect a voltmeter or multimeter across it. Move the barmagnet towards the solenoid and there should be a deflection in the voltmeter because ##\phi## changes when you keep moving the barmagnet.
or as you know, the bar magnet is also like a solenoid. The expression for magneticfield for barmagnet along axis is $$B=\frac{\mu_0}{4\pi}\frac{2m}{r^3}$$
 
So, just a little clarification, I did a little research online, is M the magnetic strength of each pole and r, I take it is the distance?

Thanks btw.
 
M is the magnetic fipole moment. Here, ##m=n(2L)I(\pi a^2)##
L is the length from midpoint to one end and 'a' is the radius. 'r' is the distance from midpoint to any point along the axis.
 
Awesome. Thank you
 

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