Calculating CuSO4*5H2O Yield from H2SO4 and Copper Reaction

[danne89]

Hi again! The problem goes like this:
How many g CuSO4*5H_2O does one get when 20 g of a 98% H2SO4 solution and copper interact, if only 85% of the cristalls is possible to use.

Cu+H_2SO_4 + 5H_2O \rightarrow CuSO_4 * 5H_2O + H_2
20*0.98=19.6
\frac{19.6}{H_2SO_4} = \frac{x}{CuSO_4*5H_2O}
x=49.87
49.87 * 0.85 = 42.39

 

[dextercioby]

I'm sorry,but the reaction is REDOX AND IT IS NOT CORRECT IN THE FORM U HAVE GIVEN.Please adjust it.

Daniel.

 

[danne89]

I'm sorry too; for being so stupid.
Cu \rightarrow Cu^{2+} + 2e^-
H_2SO_4 + 2e^- \rightarrow H_2 + SO_4^{2-}
SO_4^{2-} + Cu^{2+} \rightarrow CuSO_4
CuSO_4 + 5H_2O \rightarrow CuSO_4 + 5 H_2O
Hmm. That cannot be right. Cu is a preciouser metal then H...

 

[dextercioby]

That's right.From your reaction,there will not come out any Hydrogen.Take another chance.

Daniel.

 

[danne89]

Cu + 5 H_2SO_4 \rightarrow CuSO_4 * 5H_2O +5 SO_4^{2-}

Edit: No! It's wrong too. Bluaa

 

[dextercioby]

No.It's wrong.If i tell u the reaction products,can i trust you'll do the redox thing...?

Daniel.

P.S.Copper(II) sulphate,sulphur dioxyde and plain water.

 

[danne89]

Nooo. I can't. I even cannot locate the oxidizer.

 

[dextercioby]

Sulphate ion is the oxydizer (the sulphur gets reduced).Okay,i'll right the reaction and u'll do the REDOX THING...

Cu+2H_{2}SO_{4}\rightarrow CuSO_{4}+SO_{2}\uparrow +2H_O

You can solve your problem now,but it would be nice if you figured out how this reaction is trully going...

Daniel.