Calculating Yield of CuSO4 Crystals from Reaction of H2SO4 and CUO

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Discussion Overview

The discussion centers around calculating the yield of copper(II) sulfate (CuSO4) crystals from the reaction between sulfuric acid (H2SO4) and copper(I) oxide (CuO). Participants explore whether to use anhydrous CuSO4 or hydrated CuSO4.5H2O for theoretical yield calculations, and how to properly balance the chemical equations involved.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant questions whether to use CuSO4 or CuSO4.5H2O for yield calculations, noting the difficulty in balancing the equation with the hydrated form.
  • Several participants suggest using CuSO4.5H2O, but express uncertainty about how to display and balance the equations correctly.
  • Another participant proposes balancing the reaction with water, indicating that water is present in the experimental conditions.
  • There is a suggestion to combine two equations to arrive at a balanced reaction involving CuSO4.5H2O, but one participant points out that the coefficients should be the lowest possible, indicating a potential error in the proposed equation.
  • A later post raises a question about when to use the molar mass of CuSO4 versus CuSO4.5H2O in calculations, noting that all CuSO4 appears blue, suggesting hydration.

Areas of Agreement / Disagreement

Participants express differing opinions on whether to use CuSO4 or CuSO4.5H2O for yield calculations and how to balance the equations. The discussion remains unresolved, with multiple competing views on the correct approach.

Contextual Notes

Participants highlight limitations in their understanding of balancing equations involving hydrated and anhydrous forms of copper sulfate, as well as the implications for yield calculations.

matthew77ask
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I was tasked to calculate the yield of CuSO4 by the reaction of H2SO4 and CUO.
My equation says the it should get CUSO4 and H2O.

But should we use CUSO4.5H2O for theoretical yield instead since it is a crystal that we are calculating - if so then I could not balance the equation...

what should I use...

many thanks
 
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CuSO4.5HsO.
 
matthew77ask said:
what should I use...

CuSO4.5H2O.
 
Hi,

Logically CuSO4.5H2O., but

If I use
CuSO4.5H2O
then what to display in the equation ?

and how to balance it? or just balance without 5H20?
[why?]
 
Just balance with water, you are performing the experiment in solution - plenty of water around and it is built into the crystals.
 
Borek said:
Just balance with water, you are performing the experiment in solution - plenty of water around and it is built into the crystals.

5CuO + 5H2SO4 --> 5CuSO4 + 5H2O

CuSO4 + 5H2O --> CuSO4.5H2O

5CuO + 5H2O --> CuSO4.5H2O

correct?

thanks.
 
Coefficients should be lowest possible - so the first one is wrong.

Second is OK.

Third is not balanced, which is obvious at first sight - there is no sulfur on the left.
 
Opps!
I am trying to combine the two equations:

5CuO + 5H2SO4 --> 5CuSO4 + 5H2O

CuSO4 + 5H2O --> CuSO4.5H2O
Adding them

5CuSO4 + 5H2O --> CuSO4.5H2O

correct?

thanks.
 
Also, when we use CuSO4 for reaction calculations, when we use Mr(CuSO4) and when do we use Mr(CuSO4.5H20) ?

seems that all CuSO4 are blue - containing the 5H2O

Many thanks...
 
Last edited:
  • #10
Try with

CuO + H2SO4 + H2O ->
 

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