Calculating Decay Events in Vintage Wine from 1946 using Tritium Kinetics

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To calculate the expected decay events per minute in a vintage wine from 1946, you start with the known decay rate of tritium in surface water, which is 5.5 events per minute per 100 grams. Given tritium's half-life of 12.3 years, you need to account for the 61 years since 1946. The formula ln(N/5.5) = -(.693/12.3)(61) can be used to solve for N, representing the decay events per minute in the wine. Clarification on the expected result is needed to ensure accurate calculations.
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1. surface water contains enough tritium to show 5.5 decays events per minute per 100. g of water. Tritium has a half-life of 12.3 years. You are asked to check a vintage wine that is claimed to have been produced in 1946. How many decay events per minute should you expect to observe in 100.g of that wine?

I just need someone to point me in the right direction with this. I calculated k, but I'm having trouble figuring out how to get the number of decay events/min. Thanks.
 
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Do I just do ln(N/5.5 decay events/min x g) = -(.693/12.3)(61 years) and solve for N?
 
Have you tried? What result are you expecting?
 
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