Calculating Distance Slid on Ground with Friction | Baseball Player Example

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A baseball player slides into third base at an initial speed of 7.9 m/s, with a coefficient of kinetic friction of 0.41. To calculate the distance slid before coming to rest, the player’s mass is not needed, as it will cancel out in the equations. The relevant equations include Newton's second law and the work-energy theorem, which relates kinetic energy loss to work done against friction. The only force acting horizontally is friction, which can be expressed as Fk = μmg. Understanding these principles allows for the calculation of the distance slid using the given parameters.
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Homework Statement



A baseball player slides into third base with an initial speed of 7.9 m/s. If the coefficient of kinetic friction the player and the ground id .41, how far does the player slide before coming to rest

Homework Equations



vf^2=vi^2 + 2ad
kf=μm

The Attempt at a Solution


I tried subsituting but I need acceleration and distance. I didn't know where to go from there
 
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Are you given mass of the baseball player?
 
Ace. said:
By kf=μm do you mean Fk = μk x FN?

Note that FN is the normal force which in this case is equal to force of gravity.

This equation may also be of use to you : a = FUN / m

sorry, yeh you're right with the formula

but why is the normal force equal to gravity and what is FUN
 
Sorry, do you have mass?
 
No, no mass is given
 
Confused too said:
I tried subsituting but I need acceleration and distance.
Use Newton's 2nd law to find the acceleration. The only force acting (at least horizontally) is friction.

Just call the mass 'm'. You won't need an actual value.
 
Doc Al said:
Use Newton's 2nd law to find the acceleration. The only force acting (at least horizontally) is friction.

Just call the mass 'm'. You won't need an actual value.

I don't understand. F=ma so a=F/m but we don't have an F. I don't really understand frictional forces at all
 
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Hi Confused too! Welcome to PF! :smile:
Confused too said:
A baseball player slides into third base with an initial speed of 7.9 m/s. If the coefficient of kinetic friction the player and the ground id .41, how far does the player slide before coming to rest
Confused too said:
I don't really understand frictional forces at all

You have the coefficient of frictionk = 0.41) …

so if the mass is m, what is the friction force? :wink:

(btw, you can then use the work energy theorem)
 


tiny-tim said:
Hi Confused too! Welcome to PF! :smile:

thanks :smile:

You have the coefficient of frictionk = 0.41) …

so if the mass is m, what is the friction force? :wink:

(btw, you can then use the work energy theorem)

But we're not given m and what's the work energy theorem?
 
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Confused too said:
But we're not given m
So create an unknown for it (m?) and with luck it will cancel out of the equations later.
and what's the work energy theorem?
In this case, that the kinetic energy lost by the player is equal to the work done sliding against friction. But you might as well stick with the equations you quoted. (The second one is more accurately written kf=μmg.)
 
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