Calculating Distance Traveled with Kinetic Friction (Coefficient 0.2)

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Homework Help Overview

The problem involves a pop can sliding across a table, with an initial velocity of 2 m/s and a coefficient of kinetic friction of 0.2. The objective is to determine how far the can travels before coming to a stop, considering the effects of kinetic friction.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between net force, mass, and friction, questioning how the unknown mass affects the calculations. There is an exploration of whether the mass can be eliminated from the equations.

Discussion Status

Participants are actively engaging with the problem, with some suggesting that the mass may cancel out in the equations. There is a recognition of the friction force as the primary force acting on the can, and the discussion is focused on clarifying the implications of the given information.

Contextual Notes

The problem does not provide the mass of the pop can, which is a point of contention in the discussion. Participants are working within the constraints of the information provided in the homework statement.

iRamie
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Homework Statement


A pop can is sliding across a table and then eventually comes to a stop. If it's initial velocity is 2m/s and the coefficient of kinetic friction between the two surfaces is 0.20, how far will it travel across the table.
Vi=2m/s
Vf=0m/s
CoeffKineticFriction = 0.2

Homework Equations


Fnet = ma
(vf-vi)/t = a

The Attempt at a Solution


I know that there is a force of friction and the coefficient is 0.2, but i don't know the mass of the object to find the normal force.
 
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As you noted: Fnet = ma and Fnet = us X Fn.

Can you expand Fn? Will the unknown mass cancel?
 
edgepflow said:
As you noted: Fnet = ma and Fnet = us X Fn.

Can you expand Fn? Will the unknown mass cancel?
Nope, that's all the question says. It says "Pop Can", and there is a correct answer for it which is 1 metre.
 
What edgepflow was hinting at was that if you express the normal force in terms of the unknown mass m, then the mass will cancel from both sides of the equation. So the result is independent of mass.
 
The only force is the friction force because it is sliding there is no other force.
 
iRamie said:
The only force is the friction force because it is sliding there is no other force.

That's true...in the horizontal direction at least. I'm not sure what you're getting at with your statement.

Did you try taking our advice?
 

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