Calculating Distance Traveled with Kinetic Friction (Coefficient 0.2)

In summary, the question involves a pop can sliding across a table and coming to a stop. Its initial velocity is 2m/s and the coefficient of kinetic friction between the two surfaces is 0.20. The equations Fnet = ma and (vf-vi)/t = a are relevant, but the mass of the object is unknown. However, the normal force can be expressed in terms of the unknown mass, which will ultimately cancel out and result in an answer of 1 metre for the distance traveled across the table. The only force acting on the can is the friction force due to its sliding motion.
  • #1
iRamie
19
1

Homework Statement


A pop can is sliding across a table and then eventually comes to a stop. If it's initial velocity is 2m/s and the coefficient of kinetic friction between the two surfaces is 0.20, how far will it travel across the table.
Vi=2m/s
Vf=0m/s
CoeffKineticFriction = 0.2

Homework Equations


Fnet = ma
(vf-vi)/t = a

The Attempt at a Solution


I know that there is a force of friction and the coefficient is 0.2, but i don't know the mass of the object to find the normal force.
 
Physics news on Phys.org
  • #2
As you noted: Fnet = ma and Fnet = us X Fn.

Can you expand Fn? Will the unknown mass cancel?
 
  • #3
edgepflow said:
As you noted: Fnet = ma and Fnet = us X Fn.

Can you expand Fn? Will the unknown mass cancel?
Nope, that's all the question says. It says "Pop Can", and there is a correct answer for it which is 1 metre.
 
  • #4
What edgepflow was hinting at was that if you express the normal force in terms of the unknown mass m, then the mass will cancel from both sides of the equation. So the result is independent of mass.
 
  • #5
The only force is the friction force because it is sliding there is no other force.
 
  • #6
iRamie said:
The only force is the friction force because it is sliding there is no other force.

That's true...in the horizontal direction at least. I'm not sure what you're getting at with your statement.

Did you try taking our advice?
 

Related to Calculating Distance Traveled with Kinetic Friction (Coefficient 0.2)

1. What is friction?

Friction is a force that opposes motion between two surfaces that are in contact with each other. It can also be described as the resistance to motion caused by the roughness of the surfaces and the interlocking of their microscopic bumps and ridges.

2. Why is friction important?

Friction is important because it allows us to walk, drive, and grip objects without slipping. It also helps to slow down moving objects and bring them to a stop. Without friction, it would be difficult to control the movement of objects and perform daily tasks.

3. What factors affect the amount of friction between two surfaces?

The amount of friction between two surfaces is affected by the roughness of the surfaces, the force pushing the surfaces together, and the type of material the surfaces are made of. Additionally, the presence of lubricants or adhesives can also affect friction.

4. How can friction be reduced?

Friction can be reduced by using lubricants, such as oil or grease, to create a slippery layer between two surfaces. Smoother surfaces can also reduce friction, as there are fewer microscopic bumps and ridges to create resistance.

5. Can friction be both harmful and helpful?

Yes, friction can be both harmful and helpful. While it can cause wear and tear on objects and reduce efficiency in certain situations, it also helps us to perform tasks and control the movement of objects. For example, without friction, it would be nearly impossible to write with a pen or pencil.

Similar threads

  • Introductory Physics Homework Help
Replies
17
Views
1K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
467
  • Introductory Physics Homework Help
Replies
16
Views
4K
  • Introductory Physics Homework Help
Replies
6
Views
1K
  • Introductory Physics Homework Help
Replies
4
Views
910
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
14
Views
1K
  • Introductory Physics Homework Help
Replies
4
Views
2K
  • Introductory Physics Homework Help
Replies
28
Views
5K
Back
Top