- #1
requal
- 8
- 0
Homework Statement
For a cell in which the reaction Zn(s)+ Ni^2+(aq)->Ni(s)+ Zn^2+(aq) calculate the E(cell) when [Ni^2+]=0.05M, [Zn^2+]=0.85M.
Then, find the ratio of [Ni^2+]/[Zn^2+], when the cell is "flat"
Homework Equations
The simplified nernst equation ; E(cell)=E*(cell)-(0.0592V/n)xlogQ, log=log base 10
The Attempt at a Solution
Well I worked out the standard potential by adding half equations
Ecell=ENi-Ezn=0.51V
than because two electons are transferred, n in the nernst equation is 2.
Ecell= 0.51V-0.0592V/2log[0.85/0.05]
I plug that into my calculator, and I get 0.47V; the answer is 0.49V?
I tried doing the second part, and I got it wrong obviously, because I got the first part wrong