Calculating e3 using Node Equations: Solving for e3 in a Circuit System

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The discussion focuses on calculating the voltage e3 in a circuit system using node equations. The initial equation derived is (e3 - (-V) - e2)G1 + (e3 - e2)G2 + I = 0, which simplifies to 8e3 = -70 after manipulating the fractions. This results in e3 being calculated as -8.75. However, there is criticism regarding the lack of a clear problem statement, which is essential for context. The conversation emphasizes the importance of providing complete information when solving circuit equations.
wilsonb
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Homework Statement


I approached this by doing the node equation of e3:

(e3-(-V)-e2)G1 + (e3-e2)G2 + I = 0




Homework Equations


which gives:

e3/3 + 5/3 + e3/5 + 3 = 0

multiply out the fractions

5e3 + 25 + 3e3 + 45 = 0



The Attempt at a Solution



so:

8e3 = -70

giving e3 = -8.75
 
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wilsonb said:

Homework Statement


I approached this by doing the node equation of e3:

Approached what? There's no problem statement.
 

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