Solve Node Voltage Analysis: All G=1S, 3A Current Source

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SUMMARY

The discussion centers on solving node voltage analysis for a circuit with all conductances equal to 1S and a 3A current source. The participant presents their equations for node voltages Va, Vb, and Vc, identifying discrepancies between their calculations and the textbook solutions. Specifically, they question the inclusion of G3 in the equation for Node A and the treatment of Vc in Node C. The consensus confirms that the participant's equations are correct, indicating an error in the textbook.

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TheRedDevil18
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Homework Statement



Determine the three node voltages, va, vb, and vc, when all the conductance's are equal to 1S
Circuit Diagram:
Circuit_Diagram.jpg


The labels are a bit cut off, hope you guys can see it. The current source parallel with G2 is 3A

Homework Equations

The Attempt at a Solution


[/B]
I think their is a mistake in their solutions to the equations
These are my equations:

Node A:
Va(G1+G2+G6) - G2*Vb - G6*Vc = 9-3
Node B: -G2*Va + Vb(G2 + G3+ G4) - G4*Vc = 3
Node C: -G6*Va - G4*Vb + Vc(G4 + G5+ G6) = 7

These are the textbook solutions:

Node A:
Va(G1+G2+G3) - G2*Vb - G6*Vc = 9-3......How is G3 included when it is part of node B ?
Node B: -G2*Va + Vb(G2 + G3+ G4) - G4*Vc = 3
Node C: -G6*Va - G4*Vb - Vc(G4 + G5+ G6) = 7.....How did they get -Vc ?

My main question is, Is the textbook correct, If yes, then why ?

Thanks
 
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Your equations look fine. It looks like you've caught an error in the text.
 
gneill said:
Your equations look fine. It looks like you've caught an error in the text.

That's what I thought, thanks :)
 

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