Calculating Electric Field of Two Point Charges

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SUMMARY

The discussion centers on calculating the electric field generated by two point charges: -7e-6 C at (3 m, -2 m) and 12e-6 C at (1 m, 3 m). The initial calculations for the electric field contributions from each charge were incorrectly summed as scalars rather than vectors. The correct approach involves determining the x and y components of the electric fields and then vectorially adding them to find the resultant electric field. The constant k, representing Coulomb's law, is also a critical factor in these calculations.

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  • Understanding of Coulomb's Law and electric fields
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  • Basic knowledge of point charge properties
  • Ability to perform calculations involving square roots and basic algebra
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Zvaigzdute
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Homework Statement



A point charge of -7e-6 C is located at x = 3 m, y = -2 m. A second point charge of 12e-6 C is located at x = 1 m, y = 3 m.

Homework Equations





The Attempt at a Solution



Dq1 = sqrt(20)
Dq2 = sqrt (13)

E1 + E2= k(-7e-6)/20 + k(-7e-6)/20 = 11444.96 N/C

What am I doing wrong?

And how to find the direction ?

 
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Hi *! :smile:

(have a square-root: √ and try using the X2 icon just above the Reply box :wink:)
Zvaigzdute said:
A point charge of -7e-6 C is located at x = 3 m, y = -2 m. A second point charge of 12e-6 C is located at x = 1 m, y = 3 m.
E1 + E2= k(-7e-6)/20 + k(-7e-6)/20 = 11444.96 N/C

(I assume you're trying to find the field at (-1,0)?)

i] One of those should be +12. :rolleyes:

ii] You must add these as vectors, so use x and y components. :wink:
 
What is the question?
 

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