Calculating Electric Force: 0.15 N in +y Direction

AI Thread Summary
To calculate the electric force on a -1.2 micro Coulomb charge in a 2500 N/C electric field directed along the +y axis, the relevant formula is F = qE, where q is the charge and E is the electric field. Using this equation, the force is determined to be 0.15 N in the +y direction. The initial equation mentioned, F = k_e (Q_1 Q_2) / r^2, is not applicable in this context. The discussion emphasizes the importance of using the correct formula, often referred to as the Lorentz force law in academic settings. Understanding the distinction between these equations is crucial for solving electric force problems accurately.
samsungman
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I need help with this problem.

What is the magnitude and direction of the elctric force on a -1.2 micro Coulomb charge at a point where the electric field is 2500 N/C and is directed along the +y axis?

It has something to do with this equation:
F=k_e \frac {Q_1 Q_2} {r^2}

I got 0.15 N, in the +y direction
 
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That equation will not help you. There is an equation relating the force felt by a charge in an electric field to the magnitude of the charge and the magnitude of the electric field. In your class, it may have been called the Lorentz force law. Does that help?
 
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