Calculating Electromotive Force in a Circuit

AI Thread Summary
The discussion focuses on calculating the electromotive force (emf) in a circuit with a battery, internal resistance, and a load. The emf is determined using the formula ε = V + IR, resulting in an emf of 135.117V and a voltage across the load of 135V. Clarifications are made regarding the terminology, emphasizing that voltage does not "flow" but represents the potential difference in the circuit. It is confirmed that current remains constant in a series circuit, with the same current flowing through all components. The calculations and understanding of emf and voltage are validated in the context of circuit theory.
joel amos
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Homework Statement


A battery has a current of 3.0A flow through it. It has an internal resistance of 0.039Ω and the circuit has a load of 45Ω.
a) What is the emf?
b) What is the voltage that flows?

Homework Equations


V = ε - IR

The Attempt at a Solution


ε = V + IR
ε = (45Ω)(3A) + (3A)(0.039Ω)
ε = 135V + 0.117V

a) 135.117V
b) 135V

I'm new to emf. Does this look correct? If not, can you explain where I went awry?
 
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They asked what is the voltage that flows? Are you sure it wasn't current?
 
Not positive, but pretty sure.
 
I would check that. The voltage in a circuit doesn't "flow". The purpose of a battery is to keep the potential difference across two points in a circuit at a specific potential difference.
 
Is part "a" correct? And doesn't current remain constant?
 
Your answer looks good for part a. The current is the same everywhere in a series branch in a circuit. However, current refers to a collection of charges passing through a unit area in time t. Hence, it is often said to "flow".
 
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