Calculating Elevator Acceleration: Solve for F=ma

AI Thread Summary
To calculate the elevator's acceleration, the forces acting on a person standing on a scale must be analyzed. The scale reads 1.05 times the person's weight when the elevator accelerates upward, indicating a net upward force. The equation ΣF = 9.8(1.05m + m) is used to express the forces, where 9.8m represents gravitational force and 9.8(1.05m + m) accounts for the increased force due to acceleration. The correct approach involves equating the net force to ma, leading to the conclusion that the acceleration can be derived from the difference between gravitational force and the force exerted by the scale. Ultimately, understanding the relationship between these forces is crucial for solving the problem accurately.
Jeff Nilsson
Messages
2
Reaction score
0

Homework Statement


A person stands on a bathroom scale in a motionless elevator. When the elevator begins to move, the scale briefly reads 1.05 times the persons regular weight. Calculate the magnitude and direction of the acceleration of the elevator.

Homework Equations


F=ma

The Attempt at a Solution


Fg = 9.8m
ΣF = 9.8(1.05m + m)
0 = 1.05m + m
-m = 1.05m
-1 = 1.05

I know that's not true but I don't really know how to set up the problem
 
Physics news on Phys.org
Jeff Nilsson said:
ΣF = 9.8(1.05m + m)
Please explain your reasoning behind this equation.
What forces act on the person during the acceleration?
What acceleration results?
 
haruspex said:
Please explain your reasoning behind this equation.
What forces act on the person during the acceleration?
What acceleration results?

Actually the equation would be ΣF=9.8m-9.8(1.05m+m) according to my logic
but ΣF in this case is the difference between the force of gravity and the force of tension
the 9.8m part is to find the force of gravity on the person in the motionless elevator and the 9.8(1.05m+m) part is to find the force acting on the person when the elevator starts accelerating upward
to find ΣF you subtract the force of gravity from the fore of tension since it is larger
my physics teacher said that sometimes if you set up equations without numbers the variables will cancel out so I tried that and nothing cancels
The only number the problem gives me is 1.05 times the original weight when the elevator starts accelerating
and since the person is inside the elevator it's a system and the forces acting on the elevator vary directly with the forces acting on the person
 
Jeff Nilsson said:
the 9.8(1.05m+m) part is to find the force acting on the person when the elevator starts accelerating upward
Maybe I misunderstand your notation, but that appears to reduce to 9.8(2.05)m. Is that what you meant?

Jeff Nilsson said:
nothing cancels
It will. When you have corrected your "9.8(1.05m+m)" and written it in simplest form, equate it to "ma", as in ΣF=ma.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top