Calculating Energe stored in a Parallel Plate Capacitor

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SUMMARY

The discussion focuses on calculating the energy stored in a parallel plate capacitor with a positive charge Q on one plate and a negative charge -Q on the other. The electric field between the plates is 100 kV/m, the area of each plate is 2 × 10-3 m2, and the spacing is 6 × 10-3 m. The relevant formula for energy storage is identified as (1/2)((kε0A)/d)(Ed)2, where k is the dielectric constant, ε0 is the permittivity of free space, A is the area, d is the distance between plates, and E is the electric field strength.

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  • Knowledge of physical constants such as ε0 (permittivity of free space)
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abigailb55
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The left plate of a parallel plate capacitor carries a positive charge Q, and the right plate carries a negative charge -Q. The magnitude of the electric field between the plates is 100 kV/m. The plates each have an area of 2 × 10-3 m2, and the spacing between the plates is 6 × 10-3 m. There is no dielectric between the plates.

Calculate the energy stored in the capacitor.


I believe this is the relevant equation:
(1/2)((ke0A)/d)(Ed)^2


I really don't know what to do with this
 
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The equation look alright except for the k before \epsilon_0.

To know what to do with this equation you have to know what each letter in it represents, know the connection between the letters and the information given in the problem, do you know them?
 

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