Calculating Energy Dissipated in Copper Wire Loop Due to Magnetic Field Increase

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To calculate the average electrical energy dissipated in the resistance of a copper wire loop due to an increasing magnetic field, first determine the induced electromotive force (emf), which is given as 0.254 volts. Next, calculate the current flowing through the wire using the wire's resistance per unit length of 3.3 x 10^-2 ohms/m and the loop's dimensions. Finally, use the formula for electrical energy dissipated, which involves multiplying the current by the resistance and the time duration of the magnetic field change. This process will yield the total energy dissipated in the wire's resistance.
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A piece of copper wire is formed into a single circular loop of radius 9 cm. A magnetic field is oriented parallel to the normal to the loop, and it increases from 0 to 0.45 T in a time of 0.45 s. The wire has a resistance per unit length of 3.3 10-2 /m. What is the average electrical energy dissipated in the resistance of the wire.


I know the emf = 0.254 Volts.

How do I find the energy dissipated?
 
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Start by finding the current that flows through the wire.
 

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