Calculating Equilibrium Temperature for a Solar Hot Water System

AI Thread Summary
To calculate the equilibrium temperature of a solar collector plate, the ground-level solar intensity of 850 W/m2 must be considered along with the ambient air temperature of 20 degrees Celsius. The relevant equation involves understanding the balance between absorbed solar energy and emitted thermal radiation. The area of the collector plate is not necessary for this calculation, as the energy absorbed per square meter can be directly equated to the energy emitted. The discussion emphasizes the importance of correctly interpreting the variables in the radiation equation. Understanding these principles is crucial for determining the feasibility of a solar hot water system.
rinchan4
Messages
11
Reaction score
0

Homework Statement


You would like to put a solar hot wate system on your roof, but you'r not sure it's feasible. A reference book on solar energy shows that the ground-level solar intensity in your city is 850 W/m2 for at least 5 hours a day throughout most of the year. Assuming that a completely black collector plate loses enerty only by radiation, and that the air temp is 20 degrees celcius, what is the equilibrium temp of a collector plate directly facing the sun?



Homework Equations



Q/delta t= e sigma AT4
sigma= 5.67*10^-8



The Attempt at a Solution


So I tried to change the W/m2 into just W by multiplying by the area but i couldn't figure out the area. I think this is my biggest problem. I think once i find out how to find out the area i can plug it into the equation above and solve for T. Would this be the correct path?
 
Physics news on Phys.org
No, you do not need the area. Do you know the meaning of the formula you cited?

ehildS
 
isn't it the equation for radiation?
 
ok so i figured it out thank you for your help. :) That pointed me in the right direction.
 
Yes, it is, if you write T^4 instead of T4, but what do the letters Q, e, A, T mean?

The collector plate is totally black. What does it mean for "e"?

Now, how much energy does 1 m2 area of the collector plate gain in one second from the sun, and how much energy comes from the 20Co ambient?

This absorbed energy has to be equal to the energy emitted by 1 m2 collector plate in one second.

ehild
 
awesome thank you!
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top