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Stratosphere
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How do you Calculating the escape velocity? I googled it but they give bad instructions on how to do it. What is the formula?
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Stratosphere said:I set KE=GPE i get a velocity of 465,561 for a 10kg object. This doesn't seem right.
Stratosphere said:Every time I try using the formula i have i have to solve for V^2 and I get it to equal 35
3541. Is this right? I plug in the numbers like it says it I still don't get the right answer.
Janus said:What formula are you using?
Stratosphere said:[itex]V^{2}=\frac{2GM}{R}[/itex] to find the escape velocity of the Earth and i get, 465561.808.
Stratosphere said:Every time I try using the formula i have i have to solve for V^2 and I get it to equal 35
3541. Is this right? I plug in the numbers like it says it I still don't get the right answer.
Escape velocity is the minimum speed needed for an object to break free from the gravitational pull of a celestial body, such as a planet or moon.
The formula for escape velocity is v = √(2GM/r), where G is the gravitational constant, M is the mass of the celestial body, and r is the distance from the center of the body to the object's starting point.
No, escape velocity varies depending on the mass and size of the celestial body. For example, the escape velocity on Earth is higher than that of the Moon due to Earth's larger mass.
Yes, escape velocity is the minimum speed needed to escape a celestial body's gravitational pull. An object can exceed escape velocity if it has additional propulsion or is affected by other forces, such as a slingshot effect from a planet's gravity.
No, orbital velocity is the speed needed for an object to maintain a stable orbit around a celestial body, whereas escape velocity is the speed needed to completely break free from a celestial body's gravitational pull.