Calculating Exhaust Gas Speed for a 4200kg Rocket Launch

AI Thread Summary
To calculate the exhaust speed for a 4200kg rocket accelerating at 4.0g, the total effective acceleration must include the force to overcome Earth's gravity, resulting in a total of 5g. The thrust equation used is Fthrust = (mass flow rate) x (exhaust speed). By applying the corrected total acceleration, the exhaust speed is calculated as 7400 m/s using the formula 4200kg x 5 x 9.8 / 28kg/s. The initial calculation was incorrect due to not accounting for the additional gravitational force. The discussion highlights the importance of considering all forces acting on the rocket during launch.
pbumper1
Messages
5
Reaction score
0

Homework Statement


A 4200kg rocket is to be accelerated at 4.0g at take-off from the Earth.
If the gases can be ejected at a rate of 28 kg/s, what must be their exhaust speed?

Homework Equations



Fthrust=mv2-mv1/t2-t1

The Attempt at a Solution



Multiplied 4200kgx4x9.8/28kg/s=-5900
 
Physics news on Phys.org
Your work seems fine to me. Do you have any specific questions on this problem?
 
The answer is wrong and don't understand why it is?
 
I figured it out for future reference, since the rocket has to overcome 1g you add it to the 4g. You use the same equation. 4200x5x9.8/28=7400m/s
 
pbumper1 said:
I figured it out for future reference, since the rocket has to overcome 1g you add it to the 4g. You use the same equation. 4200x5x9.8/28=7400m/s


Good catch! Nice job.:smile:
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top