Calculating Extra Work for Hooke's Law Spring

AI Thread Summary
To calculate the extra work required to stretch a Hooke's law spring an additional 6.93 cm after initially stretching it 6.08 cm with 2.11 J of work, the force exerted by the spring must be determined. The user initially calculated force by dividing the work done by the initial stretch distance. They then multiplied this force by the additional stretch distance but questioned whether they needed to solve for the spring constant, k. Ultimately, the user resolved their confusion and confirmed they understood the solution. The discussion highlights the importance of understanding Hooke's Law and the relationship between force, work, and displacement in spring mechanics.
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Homework Statement



It takes 2.11 J of work to stretch a Hooke's law spring 6.08 cm from its unstressed length. How much the extra work is required to stretch it an additional 6.93 cm?


Homework Equations



F = -kx, W = Fd

The Attempt at a Solution



I first solved for Force by dividing 2.11J by 0.0608 m, then I just took that value and multiplied by 0.0693. I am not sure if I'm doing the correct thing. Is there a need to solve for k?

Thank you very much!
 
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nvm I got it.
 

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