Calculating Force for a Space Shuttle with Earth's Gravitational Acceleration

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To counter Earth's gravitational acceleration of 9.8 m/s² for a 10,000-kg space shuttle, a force of 98,000 Newtons is required, which is calculated correctly by multiplying mass by gravitational acceleration. The discussion clarifies that "g" represents gravitational field intensity rather than a true acceleration when not in free fall. It emphasizes the importance of understanding balanced forces in physics, where the forces acting on an object must equal each other for equilibrium. The original poster successfully applied these concepts and achieved an "A" on the quiz. This highlights the significance of grasping fundamental physics principles for problem-solving.
gnickg
I am no science or physics major but this is my first quiz. I have this problem:
How much force must be applied to accelerate a 10,000-kg space shuttle to counter the Earth's gravitational acceleration of 9.8 meters per second square?
I took 9.8m/s^2 * 10,000 for 98,000 Newtons.
Is that correct?
Your help is much appreciated!
gnickg
 
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Yep.

Followup: the space shuttle accelerates at roughly 3g's at liftoff. What's the force? (careful, its a bit of a trick question)
 
Originally posted by gnickg
I am no science or physics major but this is my first quiz. I have this problem:
How much force must be applied to accelerate a 10,000-kg space shuttle to counter the Earth's gravitational acceleration of 9.8 meters per second square?
I took 9.8m/s^2 * 10,000 for 98,000 Newtons.
Is that correct?
Your help is much appreciated!
gnickg

So far so good. Here's a conceptual helping hand: "g" is always called "acceleration due to gravity," but that's a misnomer (wrong name). An object only has an acceleration equal to "g" when it is in free fall in a vaccuum.

Think of "g" as the gravitational field intensity, and no matter what is happening, the gravitational force on something will be "mg" . A lot of people get confused by multiplying mass times an "acceleration" when the darn thing isn't going anywhere!

Hope this is helpful.
 
It's an acceleration vector field, equivalent to accelerating at 9.8 m/s2 away from a massless earth. By the equivalence principle, the difference between being stationary in a vector field and accelerating is an illusion.
gnickg this problem is about finding where forces balance, balanced forces are equal to each other- you solved it the right way.
 
Thanks everyone for your help on my physics question. I got an "A"...!
 
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