Calculating Force in Special Relativity with Proton Velocities

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SUMMARY

The discussion focuses on calculating the force required to accelerate a proton at 4.0 x 1019 m/s2 under special relativity conditions, specifically at velocities of 0.09c, 0.4c, 0.7c, and 0.97c. The relevant equations include F = dp/dt and P = γmv, where γ (gamma) accounts for relativistic effects. The initial attempts yielded correct results for the lower velocities but failed for the higher ones, indicating a need for a more refined approach to the calculations, particularly in expressing the force in terms of γ.

PREREQUISITES
  • Understanding of special relativity concepts, particularly Lorentz factor (γ).
  • Familiarity with calculus, specifically the quotient rule for derivatives.
  • Knowledge of momentum in relativistic physics (P = γmv).
  • Basic understanding of force and acceleration in physics.
NEXT STEPS
  • Learn how to derive the Lorentz factor (γ) and its implications in relativistic physics.
  • Study the application of the quotient rule in physics problems involving derivatives.
  • Research the relationship between force, momentum, and acceleration in special relativity.
  • Explore advanced examples of force calculations at relativistic speeds to solidify understanding.
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Homework Statement


Find the force necessary to give a proton an acceleration of 4.0 1019 m/s2 when the proton has the following velocities (along the same direction as the force).

We're covering special relativity and due to my lack of a brain I can't figure this simple problem out.

Velocities are .09c and .4c (I have answers the homework website likes for these ones because the v/c isn't doing much to y?)

and .7c and .97c, which I can't get right.


Homework Equations


F = dp/dt
P = ymv
(y is gamma)

The Attempt at a Solution


I tried using the quotient rule for derivatives, and got an eqn that, when plugging in the given velocities, came up with answers that it marked as correct for the first 2, but not for the 2nd 2.

F = dp/dt = m*d/dt(yv)
(B is v/c) (a is acceleration)
F = m[(a*sqrt(1-B^2) + ((1-B^2)^-.5)(B^2)(A)]/(1-B^2)

There must be a better way to do this problem... if anyone can help I would appreciate it, very angry with this problem. Thanks.
 
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IDumb said:
F = dp/dt = m*d/dt(yv)
(B is v/c) (a is acceleration)
OK.
F = m[(a*sqrt(1-B^2) + ((1-B^2)^-.5)(B^2)(A)]/(1-B^2)
Not quite sure I understand that last step. Try to simplify this expression into some final form. (Express everything in terms of γ.)
 

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